Comments by "EebstertheGreat" (@EebstertheGreat) on "The Riddle That Seems Impossible Even If You Know The Answer" video.
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@ibrahim-sj2cr No it is not. Let's do the +5 example. So if my number is 10, instead of starting on box 10, I start on box 15. Let's say I open it and find number 6. So now I go to box 11 and open that. Maybe that contains a 73, which sends me to 78, and so on. Eventually I'm guaranteed to open a box with a 10 in it, which would send me back to box 15, where I started. This will take 50 or fewer tries unless there is a loop of length >50.
This will work for any renumbering scheme, not just incrementing. Come up with some permutation of length 100, then use that to reassign all the boxes. Maybe slip 1 sends you to box 15, and slip 2 sends you to box 91, and slip 3 sends you to box 1, whatever, but it has to be a permutation (a bijection from {1,...,100} to itself). As long as every prisoner follows that same mapping, you get a solution isomorphic to the original solution, except because the labels have changed, the warden might not know how to thwart it.
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