Comments by "EebstertheGreat" (@EebstertheGreat) on "Nyquist-Shannon; The Backbone of Digital Sound" video.
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+AutoglazzoJr
It's actually very easy to define, but it isn't continuous. For instance, consider the function f:R→R defined by f(x)=1 wherever x is in [2n,2n+1) for any integer n and f(x)=0 otherwise. This is a square wave with period 2, and it is discontinuous at every integer. (It is still defined at the integers, and it is continuous everywhere else, but at the integers it is not continuous.)
For obvious reasons, no actual wave can be an ideal square wave, because the value cannot change instantaneously like that. Real waveforms that resemble square waves have very steep slopes instead of jump discontinuities and high frequency, low magnitude oscillations instead of horizontal lines. The ideal waveform is just a limit as the real waveform becomes, in a sense, increasingly more square.
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