Comments by "Toby" (@toby9999) on "Pointers in C / C++ [Full Course]" video.

  1. Not sure whether you're referring to C2[i]? He says that a lot... remember that indexes are zero based, so... C2[0] == 'H' C2[1] == 'e' C2[2] == 'i'
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  2. It might work by pure luck if the byte following already happens to be NULL. But you should always null terminate string literals else major bug looming.
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  3. printf can also output hex. Just saying. And no, d - 4 = 9
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  4. The character is 1 byte. The pointer is 4 bytes. In a 64 bit app, a pointer is typcally 8 bytes.
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  5. And your problem is...
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  6. You're referring to the 2nd byte of a 4 byte value.... so it's actually this... 00000100 00000001 2^10 + 1
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  7. Not really.
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  8. I have not encountered float = 8 bytes in 30 years of coding. I only see float=4 bytes, double=8 bytes.
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  9. In the simple case, it doesn't matter which way you write it, but you have it backward... the * belongs to the P (conceptually). The * is not the type. It is saying P is a pointer to the type. Think about this example... int X, *Y;
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  10. In 64bit code, pointers are 64bits. Be careful with casts.
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