Comments by "John Berry" (@user-ud6ui7zt3r) on "How Electricity Actually Works" video.

The ONLY BIG QUESTION that never gets answered is that when you draw the various Poynting vectors (which originate from the center of the Battery, radially, in all directions) some of the P-vectors end-up being VERY SHORT (as they make their way from a Battery terminal to a Lightbulb terminal) and some of the P-vectors end-up being VERY LONG (because they travel along JUST OUTSIDE OF the outer “skin” of a connecting wire.) Question: If the energy is carried at a uniform constant speed, by the field, then how can this uniformity be achieved when there exists a wide variation in P-vector lengths?
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@jmodified Indeed, EM signals are supposed to travel at lightspeed, along the Poynting vector paths drawn in the Veritasium illustrations. However, relative to a specified wire, some of the drawn Poynting vectors are VERY SHORT and some of the drawn Poynting vectors are VERY LONG. This being the case, you would expect that some of EM signal would arrive sooner and some of the EM signal would arrive later.
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@jmodified Specifically, focusing upon the initial battery/lightbulb example in the desert, the majority of the energy seems to flow in the SHORTEST path lengths. Now, it is said that the purpose of the wire is to severely increase the efficiency with which the energy is transferred. However, if you look at the battery/lightbulb example in the desert, there exists almost no wire at all along the SHORTEST Poynting vector path. Is my analysis/assessment correct? It would seem that, by flowing through this extremely short distance (where almost no wire exists) is the only way the (1/c) time interval can be achieved. The video information starting at 11:01 would seem to concur with my assessment. So, apparently, the first Veritasium video (in this two-part series) did not answer my Poynting vector question, but, upon review, this follow-up second video DID.
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