Comments by "MC116" (@angelmendez-rivera351) on "Principle of Mathematical Induction (ab)^n = a^n*b^n Proof" video.

  1. One should be careful to note that this is not true for arbitrary n, only for natural n, and only if a, b are elements that commute.
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  2. (a·b)^n = a^n·b^n does assume that a, b are elements of G, with (G, ·) being an Abelian power-associative magma.
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