Comments by "" (@charlesvan13) on "Spinlaunch: BUSTED (Part 2)" video.

There's no way the rocket's internals will survive 10,000 g on the centrifuge. In particular the fuel tanks will explode.
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@teksatan4699 Centripetal force is force due to acceleration. And the forces will be extreme at the rpm that they need. A rocket will have fuel and tanks, and they will be subjected to 10000g. And it will be sideways, so not in the direction of the rocket's thrust.
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@teksatan4699 The equation like most Newtonian mechanics from F=ma. You get F=mv^2/r if you use linear velocity v, where v^2 denotes length squared. Or if you use angular velocity w: F=mrw^2 which apparently is what you used. An object will travel in a straight path, constant velocity, unless a force is applied to it.
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@teksatan4699 The centripetal force will depend on just the rotational speed, not how long it gets to speed.
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@teksatan4699 I don't think so either. The centrifuge will fly apart before they get to those speeds. This is obviously the Theranose of aerospace. Next, I would like to hear what Thunderfoot thinks about the feasibility of fusion for electric power. Because the media is starting to hype it. There are political and funding motives for over hyping such things.
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@teksatan4699 Centripetal force is acceleration. In circular motion the acceleration is perpendicular to the velocity. The force on it is the force due to the acceleration by Newton's law F=ma.
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@teksatan4699 If you're rotating a weight on the end of a string, the force is that exerted by the string on the wight. And according to Newton's second law F=ma, it accelerates it. It can maintain the same speed. But the velocity is changing in circular motion. Velocity is a vector, while the speed is the magnitude of the velocity. People used to, and still do, call the force that slams you against the wall of the carnival ride that rotates, the "centrifugal force". But that's misleading. It's a fictitious force. The carnival ride car is accelerating. Thus the force comes from F=ma.
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@teksatan4699 (10,0) to (10,10) don't obviously lie on a quarter circle. If you traced a circular path from (10,0) by 10(cos t, sin t) as t goes from 0 to \pi/4, to do a 1/4 circle but the end point would be 10(\sqrt{2}/2 ,\sqrt{2}/2 ) not (10,10).
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Riding the Mars hyperloop and walking around with a Triton breather.
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They already did this in project HARP. You can get an artillery shell into suborbital space. But that isn't useful for anything. A rocket can put a satellite in orbit. A suborbital projectile is not useful in itself.
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