Comments by "Fhf Fhf" (@fhffhff) on "НеДелягин"
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{(xy-1,5)³-3,75(xy-1,5)+393 3/4=0, x+y=1;xy=1,5+(-1575+110√205)¹/³/2+(..-..)..{y=1-x,x²-x+1,5+(-1575+110√205)¹/³/2+(..-..)..=0; x=0,5±√(-1,25+(1575-110√205)¹/³/2+(..+..)..),y=0,5-+√(-1,25+(1575-110 √205)¹/³/2+(..+..)..)
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По х:2Rsin(a/2)cos(90°+0,5a-arccos (3,5/R)),2Rsin(-a/2+arccos(3,5/R)) cos(90°-a/4-0,5arccos(3,5/R)).По у: 2Rsin(a/2)sin(90°+0,5a-arccos(3,5/R)),2Rsin(-a/2+arccos(3,5/R))sin(90 °-a/4-0,5arccos(3,5/R)). (√(36-4R²sin²(a/2)cos²(-0,5a+arcc os(3,5/R)))+√(36-4R²sin²(-a/2+arc cos(3,5/R))sin²(a/4+0,5arccos(3,5/R))))²=(2Rsin(-0,5a+arccos(3,5/R))(sin(a/2)+sin(a/4+0,5arccos(3,5/R)))+7)² R[4,83;6]S=4,83²/2π..18π
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(x²+y²)(x+y-3)=2xy≤x²+y² x+y-3≤1 y≤4-x (0;3)(0;0)(3;0) {x+y=a,xy=b; (a-1)³+(-2b-3)(a-1)+2b-2=0 a-1=(-b+1+√((b-1)²+(-2b-3)³/27))¹/³+(-b+1-2√2√(-b(b²+1,125b+13,5))/3/√3)¹/³ D>0,b<0 D=0,b=0 уже рассматривал, D<0,b>0.0 a,b=(1+(2+√(10 7/27))¹/³+(2-√(107/27))¹/³;-1)
2 71/81 a-1=-2b+2,(a-1)²+(-2b+2)(a-1)+4b² -10b+1=0×(1;1)(4;4) [{y=1-x,-1+x-x²=0;{y=4-x,-4+4x-x²=0;x=2 y=2 {(0!0)(0;3)(3;0)(2;2)}
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{y=e^(2|x|),{x≠0,y≠0,a≠0, (|x|⁴+2a|x|²)e^(4|x|)=2-2a²; (4x⁴+4x³+8ax²+4ax)e^(4x)=0 x(x³+x²+2ax+a)=0[x=0,(x+1/3)³+(2a-1/3) (x+1/3)+1 2/3a-4/27=0;x=-1/3+(-5/6a+ 2/27+√(216a3+398,25a²-72a+3)/27)¹/³+(-5 /6a+2/27-√(216a³+398,25a²-72a+3)/27)¹/³ +0**+>x 0=2-2a²=>a=±1 ((-1/3+(-5/6a+2/27+√(216a3+398,25a²-72a+3)/27)¹/³+(-5/6a+2/27-√(216a³+398,25a²-7 2a+3)/27)¹/³)⁴+2a(-1/3+(-5/6a+2/27+√(2 16a3+398,25a²-72a+3)/27)¹/³+(-5/6a+2/ 27-√(216a³+398,25a²-72a+3)/27)¹/³)²)e^ (-4/3+4(-5/6a+2/27+√(216a3+398,25a² 72a+3)/27)¹/³+4(-5/6a+2/27-√(216a³+39 8,25a²-72a+3)/27)¹/³)=2-2a² -1/3+(-5/6a+ 2/27+√(216a3+398,25a²-72a+3)/27)¹/³+(-5/6a+2/27-√(216a³+398,25a²-72a+3)/27)¹/³<0 (-22,5a+2+√(216a3+398,25a²-7 2a+3))¹/³+(-22,5a+2-√(216a³+398,25a²-7 2a+3))¹/³<1 а<0,095
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