Comments by "Fhf Fhf" (@fhffhff) on "Продолжение следует"
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x¹/³=u x=u³ dz=3u²du $(0;∞)3u³/(1+u²)/(u²-√3u+1)/(u²+√3u+1)du=-0,5ln|1+u²|+0,25ln|u²-√3u+1|+0,25√3arctg((u-√3/2)/0,5)/0,5+0,25ln|u²+√3u+1|-0,25√3arctg ((u+√3/2)/0,5)/0,5(0;∞)=-∞+∞+∞+√3* π/3=-∞
3u³=A(2u⁵-2u³+2u)+B(u⁴-u²+1)+C(2u⁵+√3 u⁴+u³-u-√3)+D(u⁴+√3u³+2u²+√3u+1)+E (2u⁵-√3u⁴+u³-u+√3)+F(u⁴-√3u³+2u²-√3u+1) {A=-0,5, B=0, C=0,25,D=0,25√3, E=0,25, F=-0,25√3;
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