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Fhf Fhf
ЗЕРКАЛО
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Comments by "Fhf Fhf" (@fhffhff) on "ЗЕРКАЛО" channel.
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{F2=1962sin50°/cos(a-50°) H, F1=1962cosa/cos(a-50°) H.
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60/11=√х,х[0;120] х=3600/121
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√(2х²+2)/4/х=(х-1)/√(2х²+2) -х²+2х+1=0 х=1+√2✓
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(x²-1/2x)(x-1)=2025
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X=-y±√(5-y²) 2x+y=-y±2√(5-y²)≤5,≥-5 -1±(5-y²)-⁰,⁵*-2y=0 -+1=y+-1*->y-1*+>y
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En=1;≠(-1)^(n-1)(n-1)!e-¹=-∞
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{x=5,y=-3.
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BC=2√(AB²-25) sin(2/_1)=6/AB √(AB²-25)=3/5AB AB=25/4 BC=10√(9/16)=7,5{7,5}
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Z=1+i±(-√2-√2i)✓
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7a²xy³(x-2y)(x-4y)✓
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20-W(5²⁰ln5)/ln5=x
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(3/2 -2/3|20) (0 1|24){Х=24,У=24.
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{c=±√(ab+22),b²+103=±a√(ab+22),a²-bc=?;0=(a+22/3/b)³-(a+22/3/b) *484/3/b²+2*22³/27/b³-b³-206b- 10609/b a=-22/3/b+(-22³/b³+27b³/2+2781b-27*10609/2/b+√(-2*22³/b³(27b³/2+2781b-27*10609/2/b)+ (27/2b³+2781b-27*10609/2/b)²))¹/³/3+(..-..).. (-22/3/b+(-22³/b³+27b³/2+2781b-27*10609/2/b+√(-2*22³/b³(27b³/2+2781b-27*10609/2/b)+ (27/2b³+2781b-27*10609/2/b)²))¹/³/3+(..-..)..)²-+b√((-22³+27b⁶/2+ 2781b⁴-27*10609/2b²+√(-2*22³b³(27b⁶/2+2781b⁴-27*10609/2b²)+ (27/2b⁶+2781b⁴-27*10609/2b²)²))¹/³/3+(..-..)..)
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R²-9+1=64-R² R=6
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arccosx=u x=cosu dx=-sinudu $e^u*sinu du=e^ucosu-e^usinu+$e^usinudu $e^u* sinudu=0,5e^ucosu-0,5e^usinu+c=0,5e^arccosx*x-0,5e^arccosx*√(1-x²)+c
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√(y/x)²-3√(y/x)-1=0 y/x=(11+3√13)/2 5*11-54=1
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(4 9|1) (0 1|-1/3){У-¹=-1/3,1/х=1;{(1;-3)}
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arcsinx+x√(1-x²)-(1-x²)¹,⁵/3(0;1)=π/2+1/3
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Arcsin(1/√3),60°-arxsin(1/√3) x=√(13-12cos(60°+arxsin(√3/3)))= √(19-2√6)
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{a=1/6,b=1/3,c=0.(A+b+c)²=1/4
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En=1;∞(-2e^(-2n)/n-e^(-2n)/n²+1/n²)=2ln(1-e-²)-Li2(e-²)+π²/6
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3(x+1)²=(x+1)(x-11)[x=-1,x=-7.
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{-x²-2x+3≤0,-2x²-3x+27>0;{(x-1)(x+3)≥0 +*-*+>x (x+4,5)(x-3)<0+°-°+>x;{x(-∞;-3]U [1;∞),x(-4,5;3);x(-4,5;3]U[1;3)
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v,км/ч|t,ч|s,км в.|s/t|t|s м.|s/(t-4)|t-4|s в.+м.|s/t+s/(t-4)|1,5|s 0=t²-7t+6,t=1;6≥4 t=6(ч)
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(x²+2x-7)²-64=(x-3)(x+5)(x+1)²
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[{x=3,y=3+a;{[x=5+√(7+a),{a[-7;-3], x=5-√(7+a);{a(-3;1],x=1+√(1-a); x=1-√{1-a);y=x+a.
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X=chu,dx=shudu $dx/x⁴/√(x²-1)=$ 8du(2e^(2u)/(e^2u+1)³-2e^(2u)/(e^(2 u)+1)⁴)=-x-²(x-+√(x²-1))²+x-³(x-+√(x ²-1))³/3+c 0=e^2u-2xe^u+1,e^u=x±√(x²-1)
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Насчёт цветов скажу 1: почти все люди видят цвета одинаково.
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(a+b)/(a(a-b))*2a=2(a+b)/(a-b)
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4047(2023²+2024):5°1
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(5 2|1) (0 1|-1/3) ..=1/3{x=√2+3,y=-3√2-1.
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√4,5+√1,5 acsin(√6/8) 60°-arcsin(√6/8)✓
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Z=2ln2(ln2-i(π/2+2πn))/(ln²2+(π/2+2πn)²)
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(3 2|7) (0 1|1/2) X-¹=2{(1/2;2)}
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5/6=?/5 ?=25/6(cm)
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a(n+2)=4(a(n+1)-an) q²-4q+4=0 q=2 an=2^n(an+b)✓ bn=a(n+1)-2an=2^(n+1)a
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X,y:5 x1y1=52 (1:52)(4:13)(13;4)(52;1){(5;260)(20;65)(65;20)(260;5)}
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A1(1;2) AA1(5;0) (10/3;0) G(-2/3;2), (-4;4) y=-x-2 y=x-2xB2-2 -3=xB2 y=x+4 (2;8) y=4x-2 y=-1/4x+4,25xA2-2 12/17=xA2 y=-1/4x+1.x=-12/5,y=1 3/5 H(-12/5;1 3/5)
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{[y=2^-3,5,y=2^1,5;[x=2^1,5,2^(-7/2)=x;x+y=33/16*2^0,5
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[5;5,5) 9-4=5✓[4,5;5,5)
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-√3/27✓
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$(0;π/2)dx/(a²cos²x+b²sin²x)=$(0; =)dt/b²/((a/b)²+t²)=b-¹arctg(t/(a/b))/a(0;=)=π/2/(ab) tgx=t,x=arctgt,dx=dt/(1+t²)
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(c²-(b-a)²)(a+b-c)=-c³+c²(a+b)+c(b²-2ba +a²)-(b-a)²(b+a)≤abc c(c²-b²+3ab-a²)≥(b+ a)(c²-(a-b)²)
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h=1/(1+2+√3)=(3-√3)/6 h2=(3+√3)/6 l=hctg15°=(3-√3)/6(2+√3)=(3+√ 3)/6 l1=l-1/3=1/6+√3/6 ctga=l1/h2 =(1+√3)/6/((3+√3)/6)=1/√3 a=60° ?=15+60=75°
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2)x²+1)⁰,⁵+ln(x+√(x²+1))(0;2)=2√5 +ln(2+√5)-2
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(X+1,5(y+1))²-2,25(y+5)²=(x-6)(x+3y +9)
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-6sin²x+7sinx-2=0 sinx=(-7±1)/-12=0,5; 2/3 [x=π/6+2πn,x=5/6π+2πn,x=arcsin(2/ 3)+2πn,x=π-arcsin(2/3)+2πn;x≠±arccos(±√5/3)+2πn {π/6+2πn;5/6π+2πn}
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(a+2 -b+1|33) (A-1 2b+1|9) {A=1,y=9/(2b+1),x=11+3(b-1)/(2b+1);{a≠1,x=(b(-25a-50)-8a-16)/(b(-a-1)-1)/(a+2),y=(8a-17)/(b(-a-1)- 1). 11+3*3/9=12×{[a=-2,-24a²-133a+357=0;(8a-16)/(-a-1)=b; a=(-133±√51961)/48{(-2;32/3)((-133±√51961)/48;(-1354±6√51961)/233)}
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z=cx+c1, где с,с1 не зависит от х
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f(x,1)-f(x,x)=xf(1) n=2 f(x,y)=ax²+bx+c+a1y²+b1y {a1=0,{b1=0,-c=a+b;f(x,y)=ax²+bx-a-b✓
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