Comments by "Fhf Fhf" (@fhffhff) on "RobWords"
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[√n+√(n+1)+√(n+2)]=[√(9n+8)]
{√n+√(n+1)+√(n+2)+1≥√(9n+8),√n+√(n+1)+√(n+2)-1≤√(9n+8);
√n(√(n+1)+√(n+2)+1)≤-√((n+1)(n+ 2))-√(n+1)-√(n+2)+3n+2× n=-0,778;-0,258;-0,888× n[m²/9-8/9;(m+1)²/9-8/9),√n+√(n+1)+√(n+2)[(√(m²-8)+√(m²+1)+√(m²+10))/3; (√((m+1)²-8)+√((m+1)²+1)+√((m+1)²+10))/3),m=3,75.. m=1,6*10²⁷;1,9*10²⁹;3,2*10²⁷ m=3,√n+√(n+1)+√(n+2)[2,8..;4,03..) n[0,16..;0,88..)U[(m²-8)/9~;(m+1)²/9 -8/9~)m≥4 √n+√(n+1)+√(n+2)[4,03..; 5 17/360)
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