Comments by "Fhf Fhf" (@fhffhff) on "БОРИС БОЯРШИНОВ СО ДНА НАУКИ"
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√х^log(2)√x≥2,√x>0,x>0.x^(0,25log(2)x)≥2,[{xє(0;1),0,25log(2)x≤log(x)2;(1){x>1,0,25log(2)≥log(x)2;(1):0,25log(2)x-1/log(2)x≤0,(log²(2)x-4)/log(2)x≤0,(log(2)x 2)(log(2)x+2)/log(2)x≤0*-2+ 0°-*+2>log (2)x log(2)xє(-∞;-2]U(0;2],хє(0;1/4]U(1;4][xє(0;1/4],{x>1,хє[1/4;1)U[4;+∞);[xє(0;1/4],хє[4;+∞);xє(0;1/4]U[4;+∞)
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y=√(-x²+ax) y=√(-x2+2ax) [a=0,x=0; 2$(0;a)dx$(√(-x²+ax);√(-x²+2ax))(x²+y²)dy =2$(0;r)(r'cosф-rsinф)dф$(√(-r²cosф²+ar cosф);√(-r²cos²ф+2arcosф))r²(r'sinф+rcosф)dф=2$(0;a)((2x²/3+2ax/3)(-(x-a)²+a²) ⁰,⁵-(2/3x²+ax/3)√(-(x-a/2)²+a²/4))dx=-1/4 a⁴arcsin(-(x/a-1)²+1)⁰,⁵+1/3a²(-(x-a)²+a²) ⁰,⁵(x-a)-1/6(-(x-a)²+a²)⁰,⁵(x-a)³+a(-(x-a)²+ a²)¹,⁵/3-1/3a⁴arcsin((x-a)/a)-(x-a)a²(-(x-a) ²+a²)⁰,⁵/3-1/6√(-(x-0,5a)²+a²/4)(x-a/2)(2a- ¹(x-a/2)²-a/4)+3/32a³arcsin√(-(2x/a-1)²+ 1)-1/3a√(-(x-a/2)²+a²/4)(x-a/2)+1/96√(- (x-a/2)²+a²/4)³)|(0;a)*2=-1/6a⁴*π*2=-π/3a⁴
x=rcosф,у=rsinф r=аcosф r=2acosф (-(x/a-1)²+1)⁰,⁵=sinu x/a=1±cosu d(x/a)=-+sin udu √(-(2x/a-1)²+1)=sinu x=a/2(1±cosu) dx=-+a/2sinudu
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log(2-x)(a^(x+2)+2a^(1-x)+x-1)+log(2+x)(a^(-x+2)+2a^(1+x)-x-1)=2{2-x>0,2-x≠1,2+x>0,2+x≠1;{x<2,x≠1,x>-2,x≠-1;хє(-2;-1)U (-1;1)U(1;2)(a^2xa²+2a)/a^x≥2a√(2a) (a² +2a*a^2x)/a^x≥2a√(2a) {2a√(2a)-3>0;2a √(2a)-3>0;(2a)¹,⁵>3,2a>3^(2/3),a>0,5*3^ (2/3) ає[0,5;1]U[e;+∞)
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a+c+d-e-h
a,b,c,d
e,a-d+e+f-g
h,f,g,a+b+c+d-f-g-h
b+c+d-e-f a+c-g=h
a+b+c+d=22
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1,2,7,12 e=11
11,5 f=8
5,8,3,6 g=3
2 Можно, только не получилось.
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a²+(x-2021)²=|x-a-2021|-|x+a-2021|,[{x≥a+ 2021,a²+(x-2021)²=-2a;{хє[-а+2021;а+2021);a²+(x-2021)²=-2x+ 4042;{х<-а+2021,a²+(x-2021)²=2a;[{x≥a+ 2021,x=2021±√(-а(а+2))+*-2-*+0>а;{хє[-а+2021;а+2021);x²-4040х+2021²-4042+а²=0;{х<-а+2021,x=2021±√(-а²+2a);[а=0,х=2021,{хє[-а+2021;а+2021), х=2020±√(1-а²);{х<-а+2021,ає(0;1), a(a-1)<0 +0°-°1+>a;[a=0,x=2021,aє[0;1],х= 2020±√(1-а²);ає(0;1),х=2021-√(-а(а-2));
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log²(2)(x+1)/(2x-1)-log(2)(x+1)/(2x-1)≤0 y=log(2)(x+1)/(2x-1) y(y-1)≤0+*0-*1+>y ує(-∞;0]U[1;+∞) [{(x+1)/(2x-1)>0,(x+1)/(2x-1)≤1,(x+1)/(2x-1)≥2;[{(x+1)/(x-1/2)>0, +°-1-°+0,5>x (x-2)/(x-1/2)≥0+°0,5-*+2>x;(x-1)/(x-1/2)≤0+°0,5-*1+>x;[{хє(-∞;-1)U(0,5;+∞),хє(-∞;0,5)U[2;+∞); хє(0,5;1];[хє(-∞;-1)U[2;+∞),хє(0,5;1];хє(- ∞;-1)U(0,5;1]U[2;+∞)
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{5|x|+12|y-2|=60,y²-a²=4(y-1)-x²;[{y=7-5/12x,x≥0,y≥2;{y=-3+5/12x,x≥0,y≤2;{y=7+5/12x,x≤0,y≥2;{y=-3-5/12x,x≤0,y≤2;y ²-4y-a²+4+x²=0;y=2±√(a²-x²);ує[-3;7] √(а²- х²)≤5,а²≤25+х²,≥х² а²≥0,≤169,ає[-13;13] 2-√(а²-х²)≥-3,√(а²-х²)≤5 ає[-13;13]
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{0,5log|x|2>1,x²>0,x²≠1;{(0,5-log(2)|x|)/log(2)|x|>0,x≠0,x≠±1;{(log(2)|x|-0,5)/log(2)|x|<0,+1°2⁰,⁵-°+>|x| |x|є(-∞;1)U(2⁰,⁵;+∞) хє(-∞;-2⁰,⁵)U(-1;1)U(2⁰,⁵;+∞) хє(-∞;- 2⁰,⁵)U(-1;0)U(0;1)U(2⁰,⁵;+∞)
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1402,701,700,350,175',174,87,86,43,42',21,20,10,5,4' 21+20(1/2^4-1)/(1/2-1)=60
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