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Fhf Fhf
Александр Невзоров
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Comments by "Fhf Fhf" (@fhffhff) on "Александр Невзоров" channel.
0,037⁰,⁶=0,022..
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..=13,83..
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√(25^х-2^(3-х))≤7*2^(-х/2)-2*5^х,{25^х- 8/2^х≤49*2^-х-28*2^(-х/2)*5^х+4*25^х,(50^х-8)/2^х≥0-*log(50)8+>х;{-3*25^х-57/2^х+28*(5/√2)^х≤0,хє[log(5 0)8;+∞);{(5√2)^2x-28/3*(5√2)^x+19≥0,х є[log(50)8;+∞);{((5√2)^x-(28/3+√(28²/9-4*19))/2)((5√2)^x-(14/3-√(196-171)/3))≥0,+*log(5√2)3-*log(5√2)19/3+>xхє[log(5 0)8;+∞);{хє(-∞;log(5√2)3]U[log(5√2)(19/3);+∞),хє[log(5√2)2√2;+∞);хє[log (5√2)2√2;log(5√2)3]U[log(5√2)(19/3);+ ∞)
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Анал,говно,нет?!
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(9^x-2*3^x+4)/(3^x-5)+(2*3^(x+1)-51)/(3^x-9)≤3^x+5
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an=(1-nan)/(n+3) an=1/3 a(n+1)=2/(n+ 2)/(n+3)...+6a/(n+3)/(n+2)/(n+1)
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