Comments by "Fhf Fhf" (@fhffhff) on "Бондаренко LIVE" channel.

  1. [{а≥0,х[а(1-√2/2);2а];{а<0,х[а(1+√2/2);0]; а(1+√2/2)=2+√2 а=2 а(-1-√2/2)=2+√2 а=-2{±2}
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  2. √3/2=3/l*√(1-16/l²)+√(1-9/l²)*4/l 9/16l⁴-37,5l²+481=0,l≥4,(l²-6)²≥-156 ✓l²=(25±12)/(3/2)=74/3;26/3≥16 l=√(74/3)
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  3. $√(x²-9)/xdx=$3(-2e^u/(e^2u+1)+ch u)du=3(-2arctg(x/3±√(x²/9-1))±√(x²/9-1))+c x=3chu dx=3shudu 0=(e^u)²-2x/3 e^u+1 e^u=x/3±√(x²/9-1)
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  4. 4H=..T H≠0;6,T:2 500M+100A+29T/2+2H=555X -0,5T+2H:5 min=-2 max=18 ..=0;5;10;15 ..=0 T=4H,H=1;2 T=4;8 20A=11M+99;87≤180 M≤7;8 M=9×;3 A=6,X=4,H=2,T=8 T=4H-10 H=3;4 T=2;6 20A=11M+100;98 M=0×;2 A=6,X=3,H=4,T=6 T=4H-20 H=5;7× T=0;8× 20A=11M+109;85 M=1;5× A=6;7× X=2 T=4H-30 H=8;9 T=2;6 20A=11M+102;90 M=8;0× A=×✓ M+A+T+H-X=15×;15×;10✓{2}
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  5. √((k+1)/2)-√((k-1)/2) √(2/2)-√0+√(3/2)-√(1/2)+..+√((n+1)/2)-√((n-1)/2)=-√0,5+√(n/2)+√((n+1)/2)
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  6. у'lny/y=1 ln|lny|=x+c lny=e^xc y=e^(e^xc)
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