Comments by "Fhf Fhf" (@fhffhff) on "Честные Люди"
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(a+1)³/b+(b+1)³/c+(c+1)³/a 3(a+1)²/b-(c+1)³a-²=0 a=-0,5+√(0,25+√((c+1)³b/3))-*+>a min=(b+1)³/c+(4b-¹+b-⁰,⁵√((c+1)³/3))√(0,25+b⁰,⁵√((c+1)³/3))+2b-¹+ 1,5b-⁰,⁵√((c+1)³/3)≥3(c+1)³/c≥3/4
3(b+1)²/c+(-b-²-3,125b-¹,⁵√((c+1)³/3)-5b-¹(c+1)³/12)*(0,25+b⁰,⁵√((c+ 1)³/3))-⁰,⁵-2b-²-0,75b-¹,⁵√((c+1)³/3) =0 (-1-3,125b⁰,⁵√((c+1)³/3)-5b(c+1) ³/12)²=b¹,⁵√3/16(c+1)⁴,⁵+1+19/4b⁰, ⁵√((c+1)³/3)-3(b²+b)²/c-29/64b(c+1) ³+(9c-²-13,125/c)b⁰,⁵√((c+1)³/3)(b²+ b)²+9/4(b²+b)²/c² 6(c+1)²(c-1/2)/c²= 0 c=1/2-*+>c
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{c=-a-b,a<1/2,b<1/2,-a-1/2<b,x²+(b-1)/ax-1-b/a≥0,x²+b/(a-0,5)x+(- a-b-0,5)/(a-0,5)≥0,a>0;(a+b/2)²≤b/2-1/4,{b=1/2,a=-1/4;2/3>0
-4040ab=505
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