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Fhf Fhf
Редакция.Наука
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Comments by "Fhf Fhf" (@fhffhff) on "Редакция.Наука" channel.
x=±1/x+2πn x²-2πnx-+1=0 x=πn±√(π²n²±1) nZ,nZ\{0}
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x²=lg2+2x x²-2x-lg2=0 x=1±√(1+lg2)
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x¹⁸-x¹³+x¹⁰-x⁷+x²-x+1>0 (x²-x+1)(x¹⁶+x¹⁵-x¹³ x¹²-x¹¹+x⁹+2x⁸+x⁷-x⁶-3x⁵-2x⁴+x³+3x²+2x+( 3x+1)/(x²-x+1))>0 x(x-1)(x¹⁶+x¹⁵+x¹⁴+x¹³+ x¹²+x⁸+x⁷+x⁶+1)+1>0,x(-∞;∞)
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cos2x+cos(2/3π)=-1 cos2x=-0,5 x=±1/3π+πn
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{[x=π/2+πn,x=±π/4+2πn,x=πn;x[-π+2πm;2π m];[x=-π/2+2πn,x=-π/4+2πn,x=πn.
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6x/(x-2)-2(12x/(x-2))¹/⁴-(12x/(x-2))¹/²>0 (12x/(x-2))¹/⁴=y (y-(2+10√3/9)¹/³-(2-10√3/ 9)¹/³)y>0+°0-°(2+10√3/9)¹/³+(2-10√3/9)¹/³+>y y(-∞;0)U((2+10√3/9)¹/³+(2-10√3/9)¹/³;∞) (x+((2+10√3/9)¹/³+(2-10√3/9)¹/³)⁴/6/(1-((2+10√3/9)¹/³+(2-10√3/9)¹/³)⁴/12))/(x-2)<0+°-°+>x x(((2+10√3/9)¹/³+(2-10√3/ 9)¹/³)⁴/6/(1-((2+10√3/9)¹/³+(2-10√3/9)¹/³) ⁴/12);2)
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