Comments by "Fhf Fhf" (@fhffhff) on "Тучный Жаб"
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{х²+20х+у²-20у+75=|х²+у²-25|,х-у=а;[{хє(-∞;-5]U[0;∞),у=х+5,-5=а;{хє(-5;0) у=5-√(25-(x+5)²),х-5+√(25-(х+5)²)=а;1+0,5(25-(х+5)²)^-0,5*-2(х+5)=0,(х+5)/(25-(х+5)²)=1,(х+5)²/(25-(х+5)²)=1,(х+5)² =25-(х+5)²,(х+5)²=12,5 х+5=±√12,5,х=-5± √12,5≥-5,х=-5+√12,5+*->х максимум-5+ √12,5-5+√(25-(-5+√12,5+5)²)=-10+√12,5+√(25-12,5)=-10+√12,5+√12,5=2√12,5-10,-10+√(25-0²)=-10+5=-5,0-5+√(25-5²)=-5,ає(-5;2√12,5-10);ає[-5;2√12,5-10).
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(cosx-log(6)b)(cosx-3+3b)=0,xє[0;2π] 4 разл.корня b>0,[cosx=log6(b),cosx=3-3b;4 разл.корня log6(b)≤1,≥-1,[b≤6,b≥1/6;3- 3b≤1,≥-1,{b≥2/3,b≤4/3;bє[2/3;4/3] [х=±arc coslog6(b)+2πn,x=±arccos(3-3b)+2πn;{arccoslog6(2/3);2π-arccoslog6(2/3);0; 2π}{arccoslog6(4/3);2π-arccoslog6(4/3); π}bє[2/3;4/3),log(6)b=3-3b,/>\>b=1:0=0 bє[2/3;1)U(1;4/3)
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log5((3-x)(x²+2))≥log5(x²-7x+12)+log 5(5-x),{(3-x)(x²+2)>0,(x²-7x+12)>0,5-x>0;{x-3<0,(x-(7+√(49-4"12))/2)(x-(7-√1)/2)>0, +°3-°4+>x x<5;{x<3,хє(-∞;3)U(4;∞),x<5;х є(-∞;3).(-х+3)(х²+2)≥(х²-7х+12)*(х-5),-(х -3)(х²+2-(х-4)(х-5))≥0,(х-3)(х²+2-х²+5х+ 4х-20)≤0,(х-3)(9х-18)≤0,(х-3)(х-2)≤0 +*2*3+>х хє[2;3],хє[2;3)
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х^(1/3/√х)=9^(1/9),х=9:9^(1/3/√9)=9 ^(1/9) е^(1/3*х^-0,5lnx)'=е^(1/3*х^-0, 5lnx)(-1/6x^-1,5lnx+1/3x^-0,5*1/x)=0, x^-1,5lnx-2x^-1,5=0,lnx-2=0,x=e^2 +*->x max=(e^2)^(1/3/e)=e^(2/3/e),e²<9,x=2^ (1/2/√2)=1+√2/4*1+√2/4(√2/4-1)/2!+... =1,35..+0,35*-0,325+...=1,24>9^(1/9)=(1, 3..)^(1/3)=1,1.. 7^(1/3/√7)=7^(1/3/2,65)= 7^(1/7,95)=1,32..^(1 1/159)>1,1..x=6,141
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