Comments by "Fhf Fhf" (@fhffhff) on "Рабкор"
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X²+y²/a²=1,y=2ax-3a (2x-3)²+x⅔=1 5x²-12x+8=0 x=(12±4i)/10× y=-0,5/a(x-x0)+2ax0-3a (1+0,25/a⁴)x²-1/a² x((0,5/a²+2)x0-3)+(0,5a-²+2)²x0²-6 (0,5/a²+2)x0+8=0 x=x0+a²(-3±√(-(1+4a²)²x0²+4(3a²+12a⁴)x0-32a⁴+1))/(2a⁴+0,5) min=|a|√ (a²+0,25)|-3+√(-(1+4a²)²(x0-6a²/(1+ 4a²))²+4a⁴+1)|/2/(a⁴+0,25) x0[-1;1] -1,5/(1+4a²)+1,5≤1,5,≥0 x0[0;1] ±√(-1/4-3/8/(x0-1,5))=a≤√2/2
√(a⁴+0,25a²)(1,5/(a⁴+0,25)-(a⁴+0,2 5)-⁰,⁵) (a⁴+0,25a²)-⁰,⁵(-3a⁶-1,125a⁴+ 0,75a²+3/32+(-0,5a²+0,25a⁴-1/16)(a⁴+0,25)⁰,⁵)(a⁴+0,25)-²a=0 [a=0,{|a|≤√(-1/8+1/4√(19/3)cos(1/3arccos(-√(27/19³)))),(11a⁶+6,5a⁴-2,75a²-3/8)(13a⁶+2,5a⁴-3,25a²-3/8)=(0,5a⁴-a²-1/8)²;a=±√0,32*0+*√0,32->a min=0
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