Comments by "Fhf Fhf" (@fhffhff) on "ЭМПАТИЯ МАНУЧИ"
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y=±√(3(1-x²/16)) S(AB)=(yA+yB)/2*(xB-xA) S=(√(3(1-xA²/16))xB-+√(3 (1-xB²/16))xA-+√(3(1-xC²/16))xB±√ (3(1-xB²/16))xC-√(3(1-xA²/16))xC±√ (3(1-xC²/16))xA)/2,xB≥0,yB≥0,xA≤xC
S'(xA)=((1-xA²/16)-⁰,⁵xA/16(-xB+xC) ±√(1-xC²/16)-+√(1-xB²/16))√3/2=0
[xB=xC,xA=±√(8+0,5xBxC-+*±0,5√((16-xC²)(16-xB²)));+(-)*+(-)*-(+)>xA
√(4+0,25xBxC+xB+xC)-+*±√(4+0,25xBxC-xB-xC)
S=√3√(1-xB²/16)(|xB|+|xA|);√3(√(1- xA²/16)xB-+√(1-xB²/16)xA-+√(1-xC ²/16)xB±√(1-xB²/16)xC-√(1-xA²/16) xC±√(1-xC²/16)xA)/2
√3/8(1-xB²/16)-⁰,⁵(8-xB/2*xA-xB²)=0 xB=-xA/4+√(xA²+128)/4+*->xB
max=√3√(8-xA²/8+xA√(xA²+128)/8)(3xA+√(xA²+128))/16
64-4xA²×
S'=√3/32(8-xA²/8+xA√(xA²+128)/8)- ⁰,⁵(-xA²+64+(xA²+128)⁰,⁵xA)=0 xA=±4-*+>xA max=9✓
S=-(6√3,5+3√6-2√21-18)/8~1,08
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х≥1, 2-х=1-3√(х-1)+3(х-1)-(х-1)√(х-1), √(х-1)=(2-х-1-3х+3)/(-3-х+1),х-1=(-4х+4)²/(-х-2)², х³+4х²+4х-х²-4х-4=16х²+32х+16, х³-13х²-32х-20=0, (х-13/3)³+(-32-3*13²/3²)(х-13/3)+13³/27-(32+169/3)*13/3-20=0, х-13/3=(-2197/54+265*13/18+10+√((-40 37/54+201 7/18)²+(-265/3)³/27))^(1/3)+(-160 38/54+√((160 38/54)²-265³/27²))^(1/3),х=4 1/3+(-160 19/27+√11'539'184/54)^(1/3)+(-160 19/27-√11'539'184/54)^(1/3)=-6,34..,
169 265 160
*13 *13 *54
507 795 64
169 265 80
2197 3445|18 8640+38=8678
18 191. *8678
164 69424
162 60746
25 52068
18 69424
265 75'307'684
*265 -63'768'500
1825 11'539'184=16*
1590*721'199=16*23*37'957
530
70725
* 265
353625
144350
141450
15942125*4=63'768'500
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@snowmaiden3048 у"-ху'-у=0, (e^u*u'²+e^uu'u'')-xе^u*u'-e^u=0,u'²+u'u''-xu'-1=0, u'=-$(u'-x-1/u')dx=-u+x²/2+$dx/u'+c, u'+u-$dxu^(-1)(u')'=x²/2+c, u=ax²+bx+c, 2ax+b+ax²+bx+c-$dx/(2ax+b)=0,5x²+c, ax²+(2a+b)x+b+c-ln|x+b/2/a|/2/a=0,5x²+c, a=0,5, b=-2*0,5=-1,y=e^(0,5x²-x+c)
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