Comments by "Fhf Fhf" (@fhffhff) on "Олександр ПАЛІЙ"
channel.
-
x²y''+xy'-y=xlnx (xu')²+x(xu')'-1,25=0 (xu')'/(xu')²+1/x=0,(xu')-¹/-1+ln|x|=c xu'=1/(ln|x| -c) xu'=c1:c1²-1,25=0,c1=±√1,25 [xu'=1/(ln|x|-c),xu'=±√1,25;[u=ln|ln|x|-c|+c1,u=± √1,25ln|x|+c1;[y=(ln|x|-c)c1,y=|x|^±√1,25 c1;yp=1/4xln²x-1/4xlnx xlnx=xlnx, y=c1ln|x|-cc1+1/4xln²x-1/4xlnx;c1|x|^±√1,25+1/4 xln²x-1/4xlnx
1