Comments by "Fhf Fhf" (@fhffhff) on "Телеканал Дождь"
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{x(-1;0)y=ax²+bx+c,a,b,c<0,5 x≤y≤0,5(x²+ 1);x²+1≥2x,(x-1)²≥0 x=1,y=1:1=a+b+c,c=1 -a-b>0,a(0;0,5),b(0;0,5) y(0)=c,y(-1)=a-b+ c=1-2b (a-0,5)x²+bx+c-0,5≤0,{b²-4(a-0,5)(c-0,5)<0,a-0,5<0;{(b+2a-1)²<0, a<0,5;b+2a -1=0,b=1-2a,x≤ax²+(1-2a)x+a,-ax²-2ax-a≤0,-a(x+1)²≤0,a≥0
2020(a²+b²-c²)=2020(a²+b²-(1-a-b)²)=2020(a²+b²-1-a²-b²+2a+2b-2ab)=2020(1-4a+4a²)>=0,≤2020
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x⁵-5x³+5x=a⁵+1/a⁵ x³(x²-5)+5x-a⁵-1/a⁵=0, 5x⁴-15x²+5=0,x²=(15±√(15²-4*5*5))/10 [x²=1,5+0,5√5,x²=1,5-0,5√5;[x=±√(1,5+0,5 √5),x=±√(1,5-0,5√5);+*√(1,5+0,5√5)--√(1 ,5-0,5√5)*+*√(1,5-0,5√5)-√(1,5+0,5√5)*+>x max=-2,5√5-5,5+2,5√5+7,5=2,min=( √1,25+0,5)⁵-5(-√1,25+0,5)³+5(-√1,25+0,5)=5/2√5+11/2,max=-2,5√5-5,5,min=-2 a⁵+ 1/a⁵є(-∞;-2]U[2;∞), 1реш.,если а⁵+1/а⁵>2,5√5+5,5 (а¹⁰-(2,5√5+5,5)а⁵+1)/а⁵>0,(а⁵-(1,25√5+2,75+√(57,5+27,5√5)/2))(а⁵ (1,25√5+2,75-√(57,5+√5*27,5)/2))/а⁵>0, 0°+°..-√-°...+√+>а ає(0;(1,25√5+0,75-√(5 7,5+√5*27,5)/2)⁰,²)U((1,25√5+0,75+√(5 7,5+√5*27,5)/2)⁰,²;∞),2реш.а{(1,25√5+0 ,75-√(5 7,5+√5*27,5)/2)⁰,²;(1,25√5+0,75+ √(57,5+√5*27,5)/2)⁰,²},3 реш.а⁵+1/а⁵>-2, 5√5-5,5,(а¹⁰+(2,5√5+5,5)а⁵+1)/а⁵>0,(а⁵-(- 1,15√5-2,75+√(57,5+27,5√5)/2))(а⁵-(-1, 25√5-2,75-√(57,5+27,5√5)/2))/а⁵>0,(а-(-1, 25√5-2,75-√(57,5+27,5√5)/2)⁰,²)(а-(-1, 25√5-2,75+√(57,5+27,5√5)/2)⁰,²)/а⁵>0 ..-√..-°-..+√..+°0-°+>а ає((-1,25√5-2,75-√ (57,5+27,5√5)/2)⁰,²;(-1, 25√5-2,75+√(57 ,5+27,5√5)/2)⁰,²)U(0;∞),ає(-∞;0)U((1, 25√5+2,75-√(57,5+27,5√5)/2)⁰,²;(1,25√ 5+2,75+√(57,5+27,5√5)/2)⁰,²),ає((-1,25 √5-2,75-√(57,5+27,5√5)/2)⁰,²;(-1,25√5 2,75+√(57,5+27,5√5)/2)⁰,²)U((1,25√5+ 2,75-√(57,5+27,5√5)/2)⁰,²;(1,25√5+2,75+ √(57,5+27,5√5)/2)⁰,²),4реш.a⁵+1/a⁵=-2,5 √5+5,5,a¹⁰+(2,5√5-5,5)a⁵+1=0,a⁵=(-2,5√5+5,5±√((2,5√5-5,5)²-4*1))/2=-1,25√5+2,75 ±√(57,5-27,5√5)/2 aє{(-1,25√5+2,75±√(5 7,5-27,5)/2)⁰,²},5реш.a⁵+1/a⁵є(-2;2) 0/.
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