Comments by "Fhf Fhf" (@fhffhff) on "Аудио статьи"
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{{y}+[z]=0,8,{z}+[x]=1,2,z+x+y=4,7;{y}[0;1) [z](-0,2;0,8]=0,{y}=0,8,{z}=0,2,[x]=1 z=0,2, {x}+[y]=2,7,{x}=0,7,[y]=2 (1,7;2,8;0,2)
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|2x-1|+|2x+1|+4/√3*|y|=4, -1/2 0 1/2
2x-1+2x+1+4y/√3=4,{y=-√3x+√3,
x>=1/2,y≥0, {x>=1/2,y≥0,
2x-1+2x+1-4y/√3=4, y=√3x-√3,
x>=1/2,y≤0, {x>=1/2,y<0,
-2x+1+2x+1+4y/√3=4,{y=0,5√3,
1/2>x>=-1/2,y≥0, {0,5>x>-1/2,y≥0,
-2x+1+2x+1-4y/√3=4,{y=-0,5√3,
1/2>x>=-1/2,y≤0, { 0,5>x>-0,5,y≥0,
-2x+1-2x-1+4y/√3=4,{y=√3x+√3,
x<-1/2,y≥0, {x<-0,5,y≥0,
-2x+1-2x-1-4y/√3=4,{ y=-√3x-√3,
x<-1/2,y<0, { x<-1/2,y<0,
/-|^y\_>x
\___/
√3*1+√3*(1-0,5)*0,5*2=√3+0,5√3=1,5√3
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1,73V1,41*ln4/ln3=1,41*4*0,41/2/0,73=5,64*0,205/0,73=1,128/0,73=1,55.., 3^√3>4^√2
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y^(0,5)+y=0 k⁰,⁵+1=0,k=1, y0=ce^x yp=En= 0;∞anx^n n=2,A2x²+(8/3/√πa2+a1,5)x¹,⁵+(a1+0,75/√πa1,5)x+(a0,5+ 2/√πa1)x⁰,⁵+ a0=x²+8/3/√πx¹,⁵{a2=1,a1,5=0,a1=0, a0,5= 0,a0=0;yp=x² y=ce^c+x²
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