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Fhf Fhf
Валерий Ниминущий. Веды
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Comments by "Fhf Fhf" (@fhffhff) on "Валерий Ниминущий. Веды" channel.
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√(π√0,5)e⁴Ф((x+1)²/√0,125)(-1;∞)= √(π√0,5)е⁴*0,5
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h=3/(16√91/91)=3/16√91 EC=3/16√91 /(√0,91/5)=75/8 AE=-35/8
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