Comments by "Dr Gamma D" (@DrDeuteron) on "Kyle Hill" channel.

  1. This is a thought experiment. Space is empty, and flat.
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  2. it was not a routine test.
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  3. Lorentz contraction is not "perspective", it's physical reality (in special relativity). The string snaps. Just do the Lorentz transformation, the ships spread apart in their (average) reference frame.
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  4.  @jgreen2015  no.
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  5.  @kalikiller1771  perception and light propagation are not helpful in analyzing this problem.
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  6.  @jgreen2015  but the ships aren't traveling with a relative speed of zero in their (average) frame. The front ship is faster b/c the relativity of simultaneity.
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  7.  @jgreen2015  No, their velocities are simultaneous in the Earth frame. In either of their frames, the front ship is in the future w.r.t. to the rear, relative to the Earth's timing,
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  8.  @jgreen2015  maybe you should just do the Lorentz transformation. If something is simultaneous in the Earth's frame (say, reaching 0.9c), then it simply cannot be simultaneous in a moving frame, since the relativistic invariant is s^2 =(ct)^2 - x^2. In this case, if the string length L, the invariant is s^2 = -L^2. In the moving frame, the spatial separation is (gL)^2 where g>1 is the Lorentz factor. The time separation then must satisfy: (cT)^2 - (gL)^2 = -L^2 so that: |T| = gLv/c > 0. If you need clarification, that's fine, but if you want to argue that I am wrong: please don't. Anyone here who thinks I am wrong, is wrong. I studied this stuff under the greatest masters at the time, not from a rando youtuber.
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  9.  @jgreen2015  it's different, which is why the set up to the problem specifies that two ships have the same velocity profile in the initial frame. That's why it's 2 ships and a rope, not a long ship.
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  10.  @jgreen2015  that's the point, they are going at different speeds. If they are accelerating, they can only go a the same speed in one reference frame, as t'=gamma*(t-vx/c^2) and "x" is different for each ship.
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  11.  @jgreen2015  it's not time dilation, it's simultaneity that is the problem. You don't understand the paradox. I just posted the Lorentz transformation showing your error. Figure it out.
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  12. "41%"...have you ever heard a doctor use that many sig figs?
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  13.  @druhu4590  you need at least 10,000 ppl in your study to distinguish 41% from 40%….. that study didn’t happen.
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