Comments by "Fhf Fhf" (@fhffhff) on "ВЫХОД ЕСТЬ!"
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(x²)²-3x²+1=0,x²=(3±√(9-4*1))/2[x²=1,5 +√5/2,x²=1,5-√5/2;[x=±(√5+1)/2,x=±(√5- 1)/2; x⁵-x^-5=(√5+1)⁵/2⁵-(√5+1)^-5/2^-5= (176+80√5)/32-32/(176+80√5)=5,5+2,5 √5-1/(5,5+2,5√5)=5,5+2,5√5-(5,5-2,5√5)/(5,5²-2,5²*5)=11,=-11,=((√5-1)/2)⁵-1/(√5/ 2-1/2)⁵=(80√5-176)/32-32/(80√5-176)= 2,5√5-5,5-2(5√5+11)/4=-11,=11
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|х-3|^(х2-х)=(х-3)²,{х-3≥0,(х-3)^(х²-х-2)=1,х-3=0,{х≥3,х-3=1,х2-х-2=0, {х=3;{х<3,(х-3)^(х²-х-2)(-1)^(х2-х)=1;[{х≥3,х=3,х=4,х=(1±√(1-4*-2))/2,{х<3, х=3,х=4,[х=2, х=-1,х-3=-1,х2-х-2:2;[{х=3,х=4;х=2,х=1,х=2,4-2-2=0:2✓;{3;4;2;1}
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{(cosy-sinx+1)(tg²(x-π/3)+tg²(y+π/6))=0,(sinx-cosy)(2-sin2y+siny)=0;{[cosy=sinx-1;tg(x-π/3)=0,tg(y+π/6)=0,[sinx=cosy,{sin2y=1,siny=-1;{[y=±arccos(sinx-1)+2πr,x-π/3=πl,y+π/6=πp,[x=(π/2-y)(-1)^k+2k,π/2-y≥-π/2,≤π/2 {2y=π/2+2πn,y=-π/2+2πm,{[y=±arccos(sinx-1)+2πr,x=π/3+πl,y=-π/6+πp,[x=π/2-y+2πk,x=π/2+y+2πk,yє[0;π]{у=π/4+πn,y=-π/2+2πm;1+4n=-2+8πm,0/
{[-π/6+πp=±arccos(sin(π/3+πl)-1)+2πr, x=π/3+πl π/3+πl=π/2-y+2πk,yє[0;π],y=-π/6+πp,{-π/6=±arccos(√3/2-1)+π(2r-p), y=-π/6+π(l-2k),x=π/2+y+2πk,yє[0;π];
[{0/, x=π/3+2πk, π/6=y,0/,{0/, y=5π/6,x=8π/6+2πk;{π/3+2πk;π/6}{4π/3+2πk;5π/6}
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1/x(333/ln10-100x¹⁰⁰)=0 x=±(3,33/ln10)⁰,⁰¹°0+*->x max=3,33lg(3,33/ln10/e)=-3,33*0,..>-6,67 x=10^(n/100) 3,33n-10^n?-6,67 n=1;-2 x=10⁰,⁰¹;10-⁰,⁰²
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y'(x)=e^(xy),xy=z,y+xy'=z',y'=z'/x-z/x² z'/x-z/x²=e^z,(e^-z)'+ze^-z/x=-x,-z'/z+1/x =0,-ln|z|+ln|x|=C,z=±x/e^C=cx,z=-1/x,z=cx -1/x,y=c-1/x²
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0-3;3-5 6!/(6-5)!*2=120*6*2=720*2=1440
0,1,2,3,4,5:5!=120 1,2,3,3,4,5:3!*С(5;2)= 6*5!/2!/3!=6*20/2=60 1,2,3,4,5,0:5!=120 300
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